Answer :

First 40 positive integers divisible by 6 are 6, 12, 18, …, 240.


Sum of these numbers forms an arithmetic series 6 + 12 + 18 + … + 240.


Here, first term = a = 6


Common difference = d = 6


Sum of n terms of this arithmetic series is given by:


Sn = [2a + (n - 1)d]


Therefore sum of 40 terms of this arithmetic series is given by:


S40 = [2(6) + (40 - 1)(6)]


= 20 [12 + 234]


=20 × 246


= 4920

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