Q. 1

The first three terms of an AP are respectively (3y – 1), (3y + 5) and (5y + 1), find the value of y.

Answer :

Since, the terms are in an AP, therefore

(3y + 5) - (3y - 1) = (5y + 1) - (3y + 5)


6 = 2y - 4


2y = 10


y = 5


y = 5


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