Q. 73.6( 10 Votes )

# The sum of the first n terms of an AP is . Find its nth term and the 25th term.

Let an be the nth term of the AP.

To find: an and a25

Since, an =Sn - Sn - 1

= ( ) - ()

= 1/2 (3n2 + 5n) - 1/2 [3(n - 1)2 + 5(n - 1)]

= 1/2 (3n2 + 5n - 3n2 - 3 + 6n - 5n + 5)

= 1/2 (6n - 2)

= 3n + 1

Since an = 5n - 1

For 25th term, put n = 25, we get,

a25 = 3(25) + 1

= 75 + 1

= 76

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