Q. 1 A4.5( 41 Votes )

# Show that each of

Answer :

Here, T_{2} - T_{1} = 15 - 9 = 6

T_{3} - T_{2} = 21 - 15 = 6

T_{4} - T_{3} = 27 - 21 = 6

Since the difference between each consecutive term is same, ∴ the progression is an AP.

So, first term = 9

Common difference = 15 - 9 = 6

Next term = T_{5} = T_{4} + d = 27 + 6 = 33

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