Q. 283.7( 3 Votes )

The 17th term of an AP exceeds its 10th term by 21. The common difference of the AP is
A. 3

B. 2

C. - 3

D. - 2

Answer :

|

Let a be the first term and d be the common difference.


Given: a17 = a10 + 21


To find: common difference = d


Consider a17 = a10 + 21


a + 16d = a + 9d + 21


16d = 9d + 21


16d - 9d = 21


7d = 21


d = 3


Common difference = 3

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