Q. 283.7( 3 Votes )
The 17th term of an AP exceeds its 10th term by 21. The common difference of the AP is
A. 3
B. 2
C.  3
D.  2
Answer :

Let a be the first term and d be the common difference.
Given: a_{17} = a_{10} + 21
To find: common difference = d
Consider a_{17} = a_{10} + 21
⇒ a + 16d = a + 9d + 21
⇒ 16d = 9d + 21
⇒ 16d  9d = 21
⇒ 7d = 21
⇒ d = 3
∴ Common difference = 3
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