# The 7th term of an AP is – 1 and its 16th term is 17. The nth term of the AP isA. (3n + 8)B. (4n – 7)C. (15 – 2n)D. (2n – 15)

Let a be the first term and d be the common difference.

Given: a7 = - 1

a16 = 17

Now, Consider a7 = - 1

a + 6d = - 1 …………(1)

Consider a16 = 17

a + 15d = 17 …………(2)

Subtract equation (1) from (2), we get,

9d = 18

d = 2

Common difference = d = 2

Now, from equation (1), we get,

a = - 1 - 6d

= - 1 - 6(2)

= - 13

Now, nth term of the AP is given by

an = a + (n - 1)d

= - 13 + (n - 1)2

= 13 + 2n - 2

= 2n - 15

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