# If the sum of first m terms of an AP is (2m2 + 3m) then what is its second term?

Let Sn denotes the sum of first n terms of an AP.

Sum of first m terms = Sm = 2m2 + 3m

Then nth term is given by: an = Sn - Sn - 1

We need to find the 2nd term, so put n = 2, we get

a2 = S2 - S1

= (2(2)2 + 3(2)) - (2(1)2 + 3(1))

= 14 - 5

= 9

the second term of the AP is 9.

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