Answer :

Let the amount of money the man saved in first month = Rs. x


Now, the amount of money he saved in second month = Rs.(x + 100)


The amount of money he saved in third month = Rs.(x + + 100 + 100)


This will continue for 10 months.


We get a an AP as x , x + 100, x + 200,… up to 10 terms.


Here, first term = x


Common difference = d = 100


Number of terms = n = 10


Total amount of money saved by the man = x + (x + 100) + (x + 200) + … up to 10 terms. = Rs. 33000 (given)


Sum of 10 terms of the Arithmetic Series = 33000


S10 =33000


(10/2) × [2a + (10 - 1)d] =33000


(10/2) × [2(x) + 9(100)] =33000


5 × [2x + 900] =33000


2x + 900 =6600


2x = 6600 - 900


2x = 5700


x = 2850


Amount of money saved by the man in first month = Rs. 2850


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