Q. 14.3( 23 Votes )

Determine k so that (3k - 2), (4k - 6) and (k + 2) are three consecutive terms of an AP.

Answer :

If three terms are in AP, the difference between the terms should be equal, i.e. if a, b and c are in AP then,
b - a = c - b

Since, the terms are in an AP, therefore

(4k - 6) - (3k - 2) = (k + 2) - (4k - 6)

k - 4 = - 3k + 8

4k = 12

k = 3

k = 3

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