# Find the value of x for which (x + 2), 2x, (2x + 3) are three consecutive terms of an AP.

Given: (x + 2), 2x, (2x + 3) are three consecutive terms of an AP.

To find:
the value of x

Solution:

Let a1 = x + 2

a2 = 2x

a3 = 2x + 3

As, a1, a2 and a3 are in AP, common difference will be equal

⇒ a2 – a1 = a3 – a2

⇒ (2x) - (x + 2) = (2x + 3) - (2x)

⇒ 2x - x - 2= 2x + 3 - 2x

x - 2 = 3

x = 5

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