# If 4, x1, x2, x3, 28 are in AP then x3 = ?A. 19B. 23C. 22D. cannot be determined

Here, first term = a = 4

Last term = l = 28

Number of terms = n = 5

l = a + (n - 1)d

28 = 4 + (5 - 1)d

28 - 4 = 4d

4d = 24

d = 6

Therefore x3 = a + 3d

= 4 + 3(6)

= 4 + 18

= 22

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