Q. 44.6( 5 Votes )

If 4, x1, x2, x3, 28 are in AP then x3 = ?
A. 19

B. 23

C. 22

D. cannot be determined

Answer :

Here, first term = a = 4


Last term = l = 28


Number of terms = n = 5


l = a + (n - 1)d


28 = 4 + (5 - 1)d


28 - 4 = 4d


4d = 24


d = 6


Therefore x3 = a + 3d


= 4 + 3(6)


= 4 + 18


= 22

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