Q. 54.0( 5 Votes )

If the numbers (2n – 1), (3n + 2) and (6n – 1) are in AP, find the value of n and the numbers.

Answer :

Since, the terms are in an AP, therefore

(3n + 2) - (2n - 1) = (6n - 1) - (3n + 2)


n + 3 = 3n - 3


2n = 6


n = 3


n= 3, and hence the numbers are 5, 11, 17.


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