Q. 184.4( 7 Votes )

Find the sum of first n even natural numbers.

Answer :

First n even natural numbers are 2, 4, 6,…, 2n.

To find: sum of these n even natural numbers.

The even natural numbers forms an AP with first term 2 and common difference 2.

Now, Sum of first n terms of an AP is given by:

Sn = [2a + (n - 1)d]

where a is the first term and d is the common difference.

Sum of first n natural numbers is given by:

Sn = [2(2) + (n - 1)(2)]

= [4 + 2n - 2]

= [2n + 2]

= n (n + 1)

Sum of first n even natural numbers is n(n + 1).

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Champ Quiz | Arithmetic Progression34 mins
Champ Quiz | Arithmetic Progression30 mins
Lets Check Your Knowledge in A.P.49 mins
Arithmetic progression: Previous Year NTSE Questions34 mins
Quiz on Arithmetic Progression Quiz32 mins
Get to Know About Geometric Progression41 mins
NCERT | Solving Questions on Introduction of A.P42 mins
Arithmetic Progression Tricks and QUIZ37 mins
Quiz | Group of Questions on General Term of an A.P49 mins
Become a Master of A.P. in 45 Minutes!!47 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses