# If an denotes the nth term of the AP 3, 8, 13, 18, ... then what is the value of (a30 - a20)?A. 40B. 36C. 50D. 56

Here, First term = a = 3

Common difference = d = 8 - 2 = 5

To find: a30 – a20

So, nth term is given by:

an = a + (n - 1)d

30th term is:

a30 = 3 + (30 - 1) × 5

= 3 + 145

= 148

Now, 20th term is:

a20 = 3 + (20 - 1) × 5

= 3 + 95

= 98

Now, (a30 – a20) = 148 - 98

= 50

(a30 – a20) = 50

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