Answer :
The no of rose plants in each row can be arranged in the form of an AP as 43, 41, 39, …, 11.
Here, First term = a = 43
Common difference = d = 41 - 43 = - 2
No of terms in the AP = No of rows in the flower bed.
∴ 11 = a + (n - 1)d
⇒ 11 = 43 + (n - 1)(-2)
⇒ 11 - 43 = - 2n + 2
⇒ 11 - 43 - 2 = - 2n
⇒ 2n = 34
⇒ n = 17
∴ No of rows in the flower bed = 17
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