Q. 175.0( 2 Votes )

How many three - A. 86

B. 90

C. 96

D. 100

Answer :

The three digit numbers divisible by 9 are 108, 117, 126, …., 999.


This forms an AP with first term a = 108


and common difference = d = 9


Last term is 999.


Now, number of terms in this AP are given as:


999 = a + (n - 1)d


999 = 108 + (n - 1)9


999 - 108 = 9n - 9


891 + 9 = 9n


900 = 9n


n = 100


There are 100 three - digit numbers that are divisible by 9.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Arithmetic Progression and 'nth' Term of APArithmetic Progression and 'nth' Term of APArithmetic Progression and 'nth' Term of AP55 mins
Sum of n Terms of APSum of n Terms of APSum of n Terms of AP56 mins
Introduction of Geometric ProgressionIntroduction of Geometric ProgressionIntroduction of Geometric Progression60 mins
Imp Qs Practice For Boards (AP)Imp Qs Practice For Boards (AP)Imp Qs Practice For Boards (AP)59 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Find the indicateKC Sinha - Mathematics

Find the indicateKC Sinha - Mathematics