The differential equation is and the function that is to be proven as solution is
y = A cos2x – B sin 2x, now we find the value of .
= –2A sin 2x – 2B cos 2x
= –4A cos 2x + 4B sin 2x
Putting the values in the equation, we get,
–4A cos 2x + 4B sin 2x + 4(A cos 2x – B sin 2x) = 0,
0 = 0
As, L.H.S = R.H.S. the equation is satisfied, so hence this function is the solution of the differential equation.
Rate this question :