Q. 9

# Solve the followi

Given Differential equation is:

(x + y)(dx–dy) = dx + dy

(x + y)dx –(x + y)dy = dx + dy

(x + y–1)dx = (x + y + 1)dy

……(1)

Let us assume z = x + y

Differentiating w.r.t x on both sides we get,

……(2)

Substituting (2) in (1) we get,

Bringing like variables on same side(i.e., variable seperable technique) we get,

Integrating on both sides we get,

We know that:

(1) ∫ adx = ax + C

(2)

Since z = x + y we substitute this,

x + y + log(x + y) = 2x + C

y + log(x + y) = x + C

The solution for the given Differential equation is y + log(x + y) = x + C.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2