Q. 115.0( 1 Vote )

Show that is a solution of the differential equation= 0.

Answer :

The differential equation is and the function to be proven is the solution of equation is , now we need to find the value of .

Putting the value of the variables in the equation,

1 + c2 x2 + 2 c x – 1 – c2 – x2 – c2 x2 + c2 + x2 – 2 c x = 0

0 = 0

As, L.H.S = R.H.S. the equation is satisfied, so hence this function is the solution of the differential equation.

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