Answer :

Now separating variable x on one side and variable y on another side, we have


Adding 1 and subtracting 1 to the numerator of LHS, we get



Integrating both sides using identities:



And





Assuming ex = t and differentiating both sides we get,


exdx = dt


substituting this value in above equation



y – log(y+1) = log(1+t)


substituting t as ex


y – log(y+1) = log(1+ex) + c


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