Answer :

Given differential equation


Find: Find the general solution of this differential equation.


=


=


=


On Integrating we get,


= y – 2log|y + 2|=log |x| + log |C| ….(i)


Put y = 0, x = 2


= 0 – 2log2 = log 2 + log c


= -2 log 2 –log 2 = log C


= -3 log 2 = log c


= =log c



Put the value of C in equation (i)


Hence, y – 2log|y + 2|=


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