Q. 104.3( 45 Votes )

# Boiling point of

Answer :

Given,

Mass of water, wl = 500 g

Boiling point of water = 99.63°C (at 750 mm Hg).

Molal elevation constant, Kb = 0.52 K kg/mol

Molar mass of sucrose (C12H22O11), M2 (11 × 12 + 22 × 1 + 11 × 16) = 342 g/mol

Elevation of boiling point ΔTb = (100 + 273) - (99.63 + 273) = 0.37 K

We know that,

ΔTb = 0.37 = w2 = w2 = 121.67 g

Hence,

121.67 g (approx) Sucrose is added to 500g of water so that it boils at 100°C.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Match the terms gChemistry - Exemplar

Note : A statemenChemistry - Exemplar

Note: In the follChemistry - Exemplar

Concentration terChemistry - Exemplar