Q. 104.3( 45 Votes )

Boiling point of

Answer :

Given,


Mass of water, wl = 500 g


Boiling point of water = 99.63°C (at 750 mm Hg).


Molal elevation constant, Kb = 0.52 K kg/mol


Molar mass of sucrose (C12H22O11), M2 (11 × 12 + 22 × 1 + 11 × 16) = 342 g/mol


Elevation of boiling point ΔTb = (100 + 273) - (99.63 + 273) = 0.37 K


We know that,


ΔTb =


0.37 =


w2 =


w2 = 121.67 g


Hence,


121.67 g (approx) Sucrose is added to 500g of water so that it boils at 100°C.

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