Q. 94.0( 4 Votes )

Form the differential equation of all the circles which pass through the origin and whose centers lie on the y – axis.

Answer :

Any circle with centre at (h, k) and radius r is given by,

(x – h)2 + (y – k)2 = r2


Here centre is on y – axis, so h = 0


So, we have the equation of circle as, x2 + (y – k)2 = r2


Further, it is given that circle passes through the origin (0,0) therefore origin must satisfy the equation of circle. So, we get,


0 + k2 = r2


So, the equation of circle is x2 + (y – k)2 = k2


x2 + y2 – 2ky = 0


x2 + y2 = 2ky



Now, differentiating it with respect to x we get,







Hence, the required differential equation is


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