Answer :

Consider the differential equation


=


=


=


Let 1-y2 = t then -2y dy = dt Let log x = v



=


= .....(1)


Substitute the value of v and t in eq (2)


= …..(2)


Put x =1 and y =3 in eq (2)


=


= C =


Put the value of C in eq (2)


=


Hence, The particular solution is


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