Answer :

(i) If a differential equation is ,


then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx


(ii) ∫dx = x + c





Given:-



This is a linear differential equation, comparing it with




Q = x3


I.F = e∫Pdx



= elogx


= x


Solution of the equation is given by


y(I.F) = ∫Q.(I.F)dx + c


yx = ∫ x3xdx + c




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