Q. 155.0( 1 Vote )

Solve the following differential equations :


Answer :

(i) If a differential equation is ,


then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx


(ii) ∫tanxdx = log|secx| + c





Given:-



This is a linear differential equation, comparing it with



P = – tanx, Q = – 2 sinx


I.F = ePdx


= e∫–tanxdx


= e–log|secx|



Solution of the equation is given by


y(I.F) = ∫Q.(I.F)dx + c



ycosx = –2sinxcosxdx + c1


ycosx = –sin2xdx + c1




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