Q. 155.0( 1 Vote )

# Solve the followi

Answer :

(i) If a differential equation is ,

then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx

(ii) ∫tanxdx = log|secx| + c   Given:- This is a linear differential equation, comparing it with P = – tanx, Q = – 2 sinx

I.F = ePdx

= e∫–tanxdx

= e–log|secx| Solution of the equation is given by

y(I.F) = ∫Q.(I.F)dx + c ycosx = – 2sinxcosxdx + c1

ycosx = – sin2xdx + c1  Rate this question :

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