Q. 155.0( 1 Vote )

# Solve the followi

(i) If a differential equation is ,

then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx

(ii) ∫tanxdx = log|secx| + c

Given:-

This is a linear differential equation, comparing it with

P = – tanx, Q = – 2 sinx

I.F = ePdx

= e∫–tanxdx

= e–log|secx|

Solution of the equation is given by

y(I.F) = ∫Q.(I.F)dx + c

ycosx = –2sinxcosxdx + c1

ycosx = –sin2xdx + c1

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