Q. 36 I5.0( 1 Vote )

# Find one-paramete Given      This is a first order linear differential equation of the form Here, P = sec2x and Q = tan x sec2x

The integrating factor (I.F) of this differential equation is, We have I.F = etan x

Hence, the solution of the differential equation is,   Let tan x = t

sec2xdx = dt [Differentiating both sides]

By substituting this in the above integral, we get  Recall    yet = tet – et + c

yet × e–t = (tet – et + c)e–t

y = t – 1 + ce–t

y = tan x – 1 + ce–tan x [ t = tan x]

Thus, the solution of the given differential equation is y = tan x – 1 + ce–tan x

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses RELATED QUESTIONS :

Integrating factoMathematics - Exemplar

Solve the followiRD Sharma - Volume 2

Solve the followiMathematics - Board Papers

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiRD Sharma - Volume 2

Solve the followiMathematics - Board Papers

Solve the followiRD Sharma - Volume 2