Q. 33.7( 3 Votes )

# Solve the following equations:

Answer :

Given differential equation can be written as:

⇒ ……(1)

Homogeneous equation: A equation is said to be homogeneous if f(zx,zy) = z^{n}f(x,y) (where n is the order of the homogeneous equation).

Let us assume:

⇒

⇒

⇒

⇒ f(zx,zy) = z^{0}f(x,y)

So, given differential equation is a homogeneous differential equation.

We need a substitution to solve this type of linear equation and the substitution is y = vx.

Let us substitute this in (1)

⇒

We know that:

⇒

⇒

⇒

⇒

⇒

Bringing like variables on one side we get,

⇒

⇒

We know that:

Integrating on both sides, we get,

⇒

⇒ log(v^{2} + 1) = -logx + logC (∵ LogC is an arbitrary constant)

Since y = vx,

we get

⇒

(∵ )

Applying exponential on both sides, we get,

⇒

⇒

Cross multiplying on both sides we get,

⇒ y^{2} + x^{2} = Cx

∴ The solution for the given differential equation is **y ^{2} + x^{2} = Cx**.

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