# Solve the following differential equations:

Given Differential equation is:

……(1)

Let us assume z = x + y + 1

Differentiating w.r.t x on both the sides we get,

……(2)

Substituting (2) in (1) we get,

Bringing like variables on same (i.e, variable seperable technique) we get,

Integrating on both sides we get,

We know that and

Also ∫adx = ax + C

tan–1z = x + C

We know that z = x + y + 1 , substituting this we get,

tan–1(x + y + 1) = x + C

The solution for the given Differential equation is tan–1(x + y + 1) = x + C

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