Q. 175.0( 1 Vote )

Solve the followi

(i) If a differential equation is ,

then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx   Given:- This is a linear differential equation, comparing it with P = tanx, Q = cosx

I.F = e∫Pdx

= e∫tanxdx

= elog|secx|

= secx

Solution of the equation is given by

y(I.F) = ∫Q.(I.F)dx + c

ysecx = –∫cosx.secxdx + c  y = xcosx + Ccosx

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