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RD Sharma - Volume 2

Exercise 22.1

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Exercise 22.2

1 2 3 A 3 B 3 C 3 D 4 5 6 7 8 9 10 11 12 13 14 15 16 A 16 B 16 C 16 D 16 E 16 F 16 G 16 H 16 I 16 J 17 18 19

Exercise 22.3

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Exercise 22.4

1 2 3 4 5 6 7 8 9

Exercise 22.5

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Exercise 22.6

Exercise 22.7

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Exercise 22.8

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Exercise 22.9

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Exercise 22.10

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 A 36 B 36 C 36 D 36 E 36 F 36 G 36 H 36 I 36 J 36 K 36 L 37 A 37 B 37 C 37 D 37 E 37 F 37 G 37 H 37 I 37 J 37 K 37 L 37 M 37 N 37 O 38 39 40 41 42

Exercise 22.11

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Very short answer

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MCQ

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Q. 145.0( 2 Votes )

Find the equation

Class 12th RD Sharma - Volume 2 22. Differential Equations

Answer :

Given the differential equation

⇒

⇒

⇒

Integrating both sides we have,

⇒

⇒

⇒ log|y| + log|1 – y| = log|1 + x| + logc

⇒ log|y(1 – y)| = log|c(1 + x)|

⇒ y(1 – y) = c(1 + x) ……(1)

Since, the equation passes through (2,2), So,

2(1 – 2) = c(1 + 2)

⇒ – 2 = c×3

⇒ c =

Therefore, equation (1) becomes

y(1 – y) = (1 + x)

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