Answer :

(i) If a differential equation is ,


then y(I.F) = ∫Q.(I.F)dx + c, where I.F = e∫Pdx





Given:-



This is a linear differential equation, comparing it with




Q = log x


I.F = e∫Pdx



= elog|x|


= x, x>0


The solution of the equation is given by


y(I.F) = ∫Q.(I.F)dx + c


yx = ∫logx.x.dx + c







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