Answer :

Let the initial population be Po .

And the population after time t be P.


According to question,






Integrating both sides, we have


= k∫dt


log|P| = kt + logc……(1)


Given, we have P = 200000 when t = 1990


Putting the value in equation (1)


log|200000| = k× 1990 + logc……(2)


we have P = 250000 when t = 2000


Putting the value in equation (1)


log|250000| = k× 2000 + logc……(3)


On subtracting equation(2) from(3) we have,


log|250000| – log|200000| = k× (2000 – 1990)




……(4)


Substituting the value of k from (4) in (2), we have


log|200000| = × 1990 + logc……(5)


Substituting the value of k, log c and t = 2010 in (2), we have







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