Q. 75.0( 1 Vote )

# The population of

Let the initial population be Po .

And the population after time t be P.

According to question,    Integrating both sides, we have = k∫dt

log|P| = kt + logc……(1)

Given, we have P = 200000 when t = 1990

Putting the value in equation (1)

log|200000| = k× 1990 + logc……(2)

we have P = 250000 when t = 2000

Putting the value in equation (1)

log|250000| = k× 2000 + logc……(3)

On subtracting equation(2) from(3) we have,

log|250000| – log|200000| = k× (2000 – 1990)   ……(4)

Substituting the value of k from (4) in (2), we have

log|200000| = × 1990 + logc……(5)

Substituting the value of k, log c and t = 2010 in (2), we have     Rate this question :

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