Q. 125.0( 1 Vote )

# <span lang="EN-US

Answer :

The differential equation is and the function to be proven as the solution is

y = ex (A cosx + B sinx), we need to find the value of .

= ex(A cos x + B sin x) + ex(–A sin x + B cos x)

= ex(A cos x + B sin x) + ex(–A sin x + B cos x) + ex(–A sin x + B cos x) + ex(–A cos x – B sin x)

= 2ex(–A sin x + B cos x)

Putting the values in equation,

2ex(–A sin x + B cos x) – 2ex(A cos x + B sin x) – 2ex(–A sin x + B cos x) + 2 ex(A cos x + B sin x) = 0

0 = 0

As, L.H.S = R.H.S. the equation is satisfied, hence this function is the solution of the differential equation.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Solve the followiRD Sharma - Volume 2

tan-1xMathematics - Exemplar

The number of solMathematics - Exemplar

Find the particulMathematics - Board Papers

Solve the followiRD Sharma - Volume 2

Find the particulMathematics - Board Papers