Q. 115.0( 1 Vote )

Solve the following differential equations:


Answer :

Given Differential equation is:


……(1)


Let us assume z = x + y


Differentiate w.r.t x on both sides we get,



……(2)


Substitute(2) in (1) we get,



Bringing like variables on same side (i.e., variable seperable technique) we get,



e–zdz = dx


Integrating on both sides we get,


∫e–zdz = ∫dx


We know that:


(1) ∫adx = ax + C


(2)



–e–z = x + C


x + e–z + C = 0


Since z = x + y we substitute this,


x + e–(x + y) + C = 0


The solution for the given Differential Equation is x + e–(x + y) + C = 0.


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