Answer :



Integrate



log(y + 1) = log(x – 1) -log c


log(y + 1) + log c = log(x – 1)


Using log a + log b = log ab




Now it is given that y(1) = 2 which means when x = 1, y = 2


Substitute x = 1 and y = 2 in (a)



c =0



x – 1 = 0


So only one solution exists.

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