Answer :
Let x be the angle of depression of object A from the point O2
And y be the angle of depression of object A from the point O1
In Δ AO1C
∠O1AC + ∠AC O1 + ∠ACO1 = 180° (angle sum property)
∠O1AC + 90° + 60° = 180°
∠O1AC = 30°
Through O1 , draw O1M ∥ AC
And through O2 draw O2N∥ AC
Now O1M ∥ AC and AO1 is transversal
∴ ∠O1AC = y = 30° = ∠MO1A (vertically opposite ∠s)
Similarly, O2N∥ AC and AO2 is transversal
∠NO2 A = x = 45° = ∠O2 AB (vertically opposite angles)
∴ Angles of depression are 30° and 45°
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