Answer :


Let AB and CD be the two poles of height h meters and 2h meters respectively such that BD be a km i.e.; the distance between the two poles and P be the midpoint of BD .


Given APB = θ and CPD = 90 θ


In Δ ABP


tan θ =


tan θ = …………………1


In Δ CDP


cot (90° – θ) = PD / CD =


cot (90° – θ )=


tan θ = ………….2


Equating 1 and 2


=


8 h 2 = a2


h = m

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