# If the angle of elevation of a tower from a distance of 100 meters from its foot is 60°, then the height of the tower isA. B. C. D.

Here, angle of elevation = 60°

Distance between the foot of tower and the shadow = 100m

Let height of the tower be h meters

Angle of elevation = tan θ =

tan 60° =

√3 × 100 = h

Height of tower = 100 √3 m

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