Q. 25.0( 2 Votes )

If the angle of elevation of a tower from a distance of 100 meters from its foot is 60°, then the height of the tower is
A.

B.

C.

D.

Answer :


Here, angle of elevation = 60°


Distance between the foot of tower and the shadow = 100m


Let height of the tower be h meters


Angle of elevation = tan θ =


tan 60° =


√3 × 100 = h


Height of tower = 100 √3 m

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