# On a horizontal plane there is a vertical tower with a flag pole on the top of the tower. At a point 9 metres away from the foot of the tower the angle of elevation of the top and bottom of the flag pole are 60° and 30° respectively. Find the height of the tower and the flag pole mounted on it.

Let the height of the Flag-pole = h(m)

And height of tower = (m)

In ∆ABC,

tan 60° =

√3 =

h+ = 9√3 -------(1)

In ∆DBC,

tan 30° =

=

√3 = 9

-------(2)

Now substituting value of in eqn. (1)

h+3√3 = 9√3

h = 9√3-3√3

h = 6√3 m.

Therefore height of tower is 3√3 m. and height of flag pole is 6√3 m.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Trick to learn all Trigonometric Formulae28 mins
Champ Quiz | Trigger on Trigonometry47 mins
Fundas of Trigonometry50 mins
Champ Quiz | Trigonometry Important Questions33 mins
NCERT | Trigonometric Identities52 mins
Champ Quiz | NTSE Trigonometry50 mins
Testing the T- Ratios of Specified Angles57 mins
Foundation | Cracking Previous Year IMO QuestionsFREE Class
Basic Concept of Trigonometry43 mins
NCERT | Imp. Qs. on Trigonometry42 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses