# The length of the shadow of a tower standing on level ground is found to be 2x metres longer when the sun’s elevation is 30° than when it was 45°. The height of the tower in metres isA. B. C. D.

In Δ DBC

tan 45° = h /y

h = y ( tan 45° = 1)……….1

In ΔACD

tan 30° =

=

√3 h = 2x + h (from 1)

2x= (√3- 1) h
h =

h = (√3 +1)x meter

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