Q. 174.0( 6 Votes )

The length of the shadow of a tower standing on level ground is found to be 2x metres longer when the sun’s elevation is 30° than when it was 45°. The height of the tower in metres is
A.

B.

C.

D.

Answer :


In Δ DBC


tan 45° = h /y


h = y ( tan 45° = 1)……….1


In ΔACD


tan 30° =


=


√3 h = 2x + h (from 1)


2x= (√3- 1) h
h =


h = (√3 +1)x meter

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