Q. 655.0( 2 Votes )

As observed from the top of a 150 m tall light house, the angles of depression of two ships approaching it are 30° and 45°. If one ship is directly behind the other, find the distance between the two ships.

Answer :

In ∆ABD



tan 45° =


1 =


x = 150m ………………..(1)


In ∆ABC


tan 30° =


=


x + y = 150√3 ………………..(2)


On substituting value of x from eqn (1) in eqn (2), we get


150 + y = 150√3


y = 150 (√3 - 1) 109.8m


Therefore the distance between two ships is 109.8m


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