Q. 194.1( 27 Votes )

# A tree breaks due

Answer :

let the broken part be DB.

Distance from the foot of the tree and point C is 8 cm.

BC = 8 cm

Height of tree = Height of broken part + height of the remaining tree= DC + DB

In ∆DBC,

tan 30° =

=

---------(1)

Cos 30° =

=

h =

Height of tree =

=

=

=

**Height of tree = 8√3 m**

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