Q. 6

In Fig. 12.58, what are the angles of depression from the observing positions O1 and O2 of the object at A?


Answer :


Let x be the angle of depression of object A from the point O2


And y be the angle of depression of object A from the point O1


In Δ AO1C


O1AC + AC O1 + ACO1 = 180° (angle sum property)


O1AC + 90° + 60° = 180°


O1AC = 30°


Through O1 , draw O1M AC


And through O2 draw O2N AC


Now O1M AC and AO1 is transversal


O1AC = y = 30° = MO1A (vertically opposite s)


Similarly, O2N AC and AO2 is transversal


NO2 A = x = 45° = O2 AB (vertically opposite angles)


Angles of depression are 30° and 45°


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