Q. 234.4( 27 Votes )

The shadow of a tower standing on level ground is found to be 40 m longer when Sun’s altitude is 30° than when it was 60°. Find the height of the tower.

Answer :

Let the height of tower = h (m)
Since the tower is vertical to the ground.
∠ABC = 90°
We know, in a right-angle triangle,

In ∆ABC,



√3h = 40 ---------------(1)

In ∆ABD,

√3 =

h =√3 -------(2)

on substituting the value of h from eqn. (2) in eqn. (1)

h = √3× (√3h-40)

h = 3h-40√3

2h = 40√3

h = 20√3 m.

Therefore the height of the tower is 20√3 m.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Trick to learn all Trigonometric Formulae28 mins
Champ Quiz | Trigger on Trigonometry47 mins
Fundas of Trigonometry50 mins
Champ Quiz | Trigonometry Important Questions33 mins
NCERT | Trigonometric Identities52 mins
Champ Quiz | NTSE Trigonometry50 mins
Testing the T- Ratios of Specified Angles57 mins
Foundation | Cracking Previous Year IMO QuestionsFREE Class
Basic Concept of Trigonometry43 mins
NCERT | Imp. Qs. on Trigonometry42 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses