Answer :

In the fig CE is the height of the pole and x be the distance between tower and pole.


tan 45° =

1 =

x = 50-h ----- (1)


tan 60° =

√3 =

x = -----(2)

On substituting value of x in eqn (1), we get

50 – h =

h = 50 -


Therefore the height of the pole is 21.13m

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