Q. 95.0( 1 Vote )

# From the top of a cliff 25 m high the angle of elevation of a tower is found to be equal to the angle of depression of the foot of the tower. The height of the tower isA. 25 mB. 50 mC. 75 mD. 100 m

Here AB = 25 m is cliff and CE = (25 + x) m is tower

tan θ = …………….1

In Δ ABC

tan θ = …………….. 2

From 1 and 2

x =25 m

Total height of tower is 25 + x = 25 +25 = 50 m

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