# The angle of elevation of the top of a hill at the foot of a tower is 60° and the angle of elevation of the top of the tower from the foot of the hill is 30°. If the tower is 50 m high, what is the height of the hill?

In the fig DC is the tower and AB is the hill.

In ∆DCB

tan 30° =

=

BC = 50√3 m

In ∆ABC

tan 60° =

√3 =

AB = 50√3× √3 m 150m

Therefore the distance between tower and hill is 50√3m and height of hill is 150m

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