Q. 305.0( 4 Votes )
The angle of elevation of the top of the building from the foot of the tower is 30° and the angle of the top of the tower from the foot of the building is 60°. If the tower is 50 m high, find the height of the building.
Let AB be the building of height 50 m. and tower of height h (m.)
tan 60° =
Now in ∆DCB
tan 30° =
On substituting value of in eqn. (1)
Therefore height of tower is m.
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