Q. 70

# Two ships are the

In the fig AB is the light house of height of 200m.

In ∆AED

tan 45° =

1 =

x = 200m ………………….(1)

In ∆ABC

tan 60° =

√3 =

√3y = 200

y =

On multiplying and dividing by √3, we get

y = m

Therefore the distance between two ships is:

DC = x + y

x + y = 200 +

= 315.47m

Therefore the distance between two ships is 315.47m

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